3h^2+48h-2160=0

Solution for 3h^2+48h-2160=0 equation:

3h^2+48h-2160=0

a = 3; b = 48; c = -2160;
Δ = b2-4ac
Δ = 482-4·3·(-2160)
Δ = 28224
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{28224}=168$
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(48)-168}{2*3}=\frac{-216}{6}
=-36
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(48)+168}{2*3}=\frac{120}{6}
=20
$